更新年兽升级判断逻辑

This commit is contained in:
anonymous
2021-01-23 10:39:45 +08:00
parent d8141634bd
commit bc15bce12d

View File

@@ -190,6 +190,13 @@ async function doTask() {
} else if(item.status===2){
console.log(`${item.taskName}已做完`)
}
}else if (item.taskType === 13) {
if (item.status === 1) {
console.log(`准备做此任务:${item.taskName}`)
await collectScore(item.taskId, "1");
} else if(item.status===2){
console.log(`${item.taskName}已做完`)
}
}
}
}
@@ -259,7 +266,7 @@ function getHomeData(info=false) {
$.secretp = null
return
}
console.log(`当前爆竹${$.userInfo.raiseInfo.remainScore}🧨,下一关需要${$.userInfo.raiseInfo.nextLevelScore}🧨`)
console.log(`当前爆竹${$.userInfo.raiseInfo.remainScore}🧨,下一关需要${$.userInfo.raiseInfo.nextLevelScore-$.userInfo.raiseInfo.curLevelStartScore}🧨`)
if(info) {
message += `当前爆竹${$.userInfo.raiseInfo.remainScore}🧨\n`
@@ -269,8 +276,8 @@ function getHomeData(info=false) {
console.log(`可收取的爆竹大于0去收取爆竹`)
await collectProduceScore()
}
if(parseInt($.userInfo.raiseInfo.remainScore) >= parseInt($.userInfo.raiseInfo.curLevelStartScore)){
console.log(`去升级`)
if(parseInt($.userInfo.raiseInfo.remainScore) >= parseInt($.userInfo.raiseInfo.nextLevelScore-$.userInfo.raiseInfo.curLevelStartScore)){
console.log(`当前爆竹🧨大于升级所需爆竹🧨,去升级`)
await $.wait(2000)
await raise()
}